Question
Use the image to answer the question.
Top of the chart:
R3
R2
R1
bottom of the chart:
+ -
Triangle V
Complete the chart for this circuit:
Resistance (Ohms) Potential Difference (V)
10
5
5
O
Item
R1
R2
R3
Battery
(1 point)
Item
R1
R2
R3
Battery
Current (A)
4
Resistance (Ohms)
2.5
2
5
Potential Difference (V)
10
10
10
10
Current (A)
4
5
2
11
4
O
Item
R1
R2
R3
Battery
Resistance (Ohms)
40
50
5
Potential Difference (V)
10
10
10
10
Current (A)
5
0.5
9.5
O
Item
R
R2
R3
Resistance (Ohms)
2.5
2
5
Potential Difference (V)
10
10
5
Current (A)
4
5
1
Battery
10
10
Item
R1
R2
R3
Battery
Resistance (Ohms)
0.4
0.5
5
Potential Difference (V)
10
10
10
10
Current (A)
4
5
50
59
Top of the chart:
R3
R2
R1
bottom of the chart:
+ -
Triangle V
Complete the chart for this circuit:
Resistance (Ohms) Potential Difference (V)
10
5
5
O
Item
R1
R2
R3
Battery
(1 point)
Item
R1
R2
R3
Battery
Current (A)
4
Resistance (Ohms)
2.5
2
5
Potential Difference (V)
10
10
10
10
Current (A)
4
5
2
11
4
O
Item
R1
R2
R3
Battery
Resistance (Ohms)
40
50
5
Potential Difference (V)
10
10
10
10
Current (A)
5
0.5
9.5
O
Item
R
R2
R3
Resistance (Ohms)
2.5
2
5
Potential Difference (V)
10
10
5
Current (A)
4
5
1
Battery
10
10
Item
R1
R2
R3
Battery
Resistance (Ohms)
0.4
0.5
5
Potential Difference (V)
10
10
10
10
Current (A)
4
5
50
59
Answers
GPT-4o mini
To complete the chart for the given circuit, let’s analyze each circuit section and fill in the required values of Resistance (Ohms), Potential Difference (V), and Current (A) for the components and the battery.
### Given Data Overview:
1. **For R1, R2, R3, and Battery**
- Resistance: R1 = 40 Ω, R2 = 50 Ω, R3 = 5 Ω
- Potential Difference: Battery = 10 V across each component.
- We need to find the current through each component.
### Using Ohm's Law:
Ohm’s law states that \( V = I \times R \), so \( I = \frac{V}{R} \).
### Current Calculation:
- **For R1 (40 Ω):**
\[
I_{R1} = \frac{10 V}{40 Ω} = 0.25 A
\]
- **For R2 (50 Ω):**
\[
I_{R2} = \frac{10 V}{50 Ω} = 0.2 A
\]
- **For R3 (5 Ω):**
\[
I_{R3} = \frac{10 V}{5 Ω} = 2 A
\]
- **For Battery (as a total):**
The total current supplied by the battery can be calculated as the sum of the currents through parallel branches (if applicable) or series.
For R1, R2, and R3, we can assume either series or parallel configuration based on how the problem is framed.
### Potential & Current for the Chart:
Let's summarize the values gathered from the above calculations:
| Item | Resistance (Ω) | Potential Difference (V) | Current (A) |
|--------|----------------|--------------------------|--------------|
| R1 | 40 | 10 | 0.25 |
| R2 | 50 | 10 | 0.2 |
| R3 | 5 | 10 | 2 |
| Battery | N/A | 10 | Total = 0.25 A Total Current remains as an addition of all branch currents or as a function of series or parallel total current.
### Final Chart:
| Item | Resistance (Ω) | Potential Difference (V) | Current (A) |
|--------|----------------|--------------------------|--------------|
| R1 | 40 | 10 | 0.25 |
| R2 | 50 | 10 | 0.2 |
| R3 | 5 | 10 | 2 |
| Battery | N/A | 10 | 2.45 |
Make sure you validate if the current division is effective by configuring whether the circuit was designed in a series or parallel position, and adapt the values accordingly based on the circuit configuration.
### Given Data Overview:
1. **For R1, R2, R3, and Battery**
- Resistance: R1 = 40 Ω, R2 = 50 Ω, R3 = 5 Ω
- Potential Difference: Battery = 10 V across each component.
- We need to find the current through each component.
### Using Ohm's Law:
Ohm’s law states that \( V = I \times R \), so \( I = \frac{V}{R} \).
### Current Calculation:
- **For R1 (40 Ω):**
\[
I_{R1} = \frac{10 V}{40 Ω} = 0.25 A
\]
- **For R2 (50 Ω):**
\[
I_{R2} = \frac{10 V}{50 Ω} = 0.2 A
\]
- **For R3 (5 Ω):**
\[
I_{R3} = \frac{10 V}{5 Ω} = 2 A
\]
- **For Battery (as a total):**
The total current supplied by the battery can be calculated as the sum of the currents through parallel branches (if applicable) or series.
For R1, R2, and R3, we can assume either series or parallel configuration based on how the problem is framed.
### Potential & Current for the Chart:
Let's summarize the values gathered from the above calculations:
| Item | Resistance (Ω) | Potential Difference (V) | Current (A) |
|--------|----------------|--------------------------|--------------|
| R1 | 40 | 10 | 0.25 |
| R2 | 50 | 10 | 0.2 |
| R3 | 5 | 10 | 2 |
| Battery | N/A | 10 | Total = 0.25 A Total Current remains as an addition of all branch currents or as a function of series or parallel total current.
### Final Chart:
| Item | Resistance (Ω) | Potential Difference (V) | Current (A) |
|--------|----------------|--------------------------|--------------|
| R1 | 40 | 10 | 0.25 |
| R2 | 50 | 10 | 0.2 |
| R3 | 5 | 10 | 2 |
| Battery | N/A | 10 | 2.45 |
Make sure you validate if the current division is effective by configuring whether the circuit was designed in a series or parallel position, and adapt the values accordingly based on the circuit configuration.