To find the probability that Tabitha chooses a four-legged pet (which can only be a cat or a dog) and chooses a toy for it, we need to analyze the options available to her.
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Types of Pets:
- Cat (4-legged)
- Dog (4-legged)
- Fish (not 4-legged)
Hence, there are 2 options for four-legged pets (cat and dog) and 1 option for a non-four-legged pet (fish).
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Choices of Items:
- For the chosen pet, she can choose either a toy or a book.
- Therefore, for each pet type, she has 2 options:
- Toy
- Book
So, let's summarize:
- If she chooses a cat:
- Cat + Toy
- Cat + Book
- If she chooses a dog:
- Dog + Toy
- Dog + Book
- If she chooses a fish:
- Fish + Toy
- Fish + Book
From this, we can see the total combinations are:
- Cat + Toy
- Cat + Book
- Dog + Toy
- Dog + Book
- Fish + Toy
- Fish + Book
Thus, there are a total of \( 3 \text{ (pets)} \times 2 \text{ (items per pet)} = 6 \text{ total combinations} \).
Now, we want to find only the combinations where she chooses a four-legged pet and a toy:
- Cat + Toy
- Dog + Toy
There are 2 combinations that fit the criteria (four-legged pet + toy).
Now we can calculate the probability:
- Total favorable outcomes = 2 (Cat + Toy and Dog + Toy)
- Total possible outcomes = 6
Thus, the probability \( P \) is given by: \[ P(\text{four-legged pet and toy}) = \frac{\text{favorable outcomes}}{\text{total outcomes}} = \frac{2}{6} = \frac{1}{3} \]
Therefore, the probability that Tabitha chooses a four-legged pet and a toy for it is \(\frac{1}{3}\).
If options A, B, C, and D correspond to specific numerical values or other formats, please provide them, and I can help you identify the correct one.
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