To determine the probability of Daniel drawing a card numbered 1 or 2 and a yellow tile, we first need to identify the total number of possible outcomes and then the number of favorable outcomes.
From the table, we can see the outcomes:
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Total Outcomes: There are 12 total outcomes since there are 3 cards (1, 2, 3) and 4 colored tiles (Red, Blue, Yellow, Green):
- Card 1: 1, Red; 1, Blue; 1, Yellow; 1, Green (4 outcomes)
- Card 2: 2, Red; 2, Blue; 2, Yellow; 2, Green (4 outcomes)
- Card 3: 3, Red; 3, Blue; 3, Yellow; 3, Green (4 outcomes)
Therefore, there are \( 3 \text{ (cards)} \times 4 \text{ (tiles)} = 12 \text{ (total outcomes)} \).
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Favorable Outcomes: We need to count the outcomes that consist of either card 1 or card 2 and a yellow tile:
- For card 1: 1, Yellow (1 outcome)
- For card 2: 2, Yellow (1 outcome)
This gives us a total of \( 1 + 1 = 2 \) favorable outcomes.
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Calculating Probability: Probability is calculated using the formula:
\[ P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Plugging in our values:
\[ P(\text{drawing card 1 or 2 and yellow tile}) = \frac{2}{12} = \frac{1}{6} \]
Thus, the final answer is:
Probability = \(\frac{1}{6}\)
If options A, B, C, D were to represent numerical values (e.g., \(\frac{1}{6}\)), you should select the one corresponding to this probability.
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