To determine the probability that Everett rolls an even number and Finley draws a blue disk, we first need to find the individual probabilities for each event.
Step 1: Calculate the probability of Everett rolling an even number.
The numbers on the block are 1, 2, 3, 4, 5, and 6. The even numbers in this range are 2, 4, and 6.
So, the number of favorable outcomes (even numbers) = 3 (which are 2, 4, and 6).
Total possible outcomes when rolling the block = 6.
The probability of rolling an even number (P(Even)) is: \[ P(Even) = \frac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}} = \frac{3}{6} = \frac{1}{2}. \]
Step 2: Calculate the probability of Finley drawing a blue disk.
Finley has three disks: one blue, one red, and one yellow.
The number of favorable outcomes (drawing a blue disk) = 1 (which is the blue disk).
Total possible outcomes when drawing a disk = 3.
The probability of drawing a blue disk (P(Blue)) is: \[ P(Blue) = \frac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}} = \frac{1}{3}. \]
Step 3: Calculate the combined probability of both events occurring.
The events (rolling an even number and drawing a blue disk) are independent, so we can multiply their probabilities:
\[ P(Even \text{ and } Blue) = P(Even) \times P(Blue) = \frac{1}{2} \times \frac{1}{3} = \frac{1}{6}. \]
Conclusion
The probability that Everett rolls an even number and Finley draws a blue disk is \(\frac{1}{6}\). Since the answer choices (A, B, C, D) are not provided, you would want to match this result, \(\frac{1}{6}\), to the correct option.
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