To find the experimental probability of drawing a number 9 counter followed by a number 3 counter, we first need to determine the number of times each counter was drawn, as well as the total number of draws.
From the data provided:
- The counter number 9 was drawn 2 times.
- The counter number 3 was drawn 3 times.
- The total number of draws is 25.
The experimental probability of drawing a number 9 counter is calculated by taking the number of times the 9 counter was drawn and dividing it by the total number of draws:
\[ P(9) = \frac{\text{Number of times 9 was drawn}}{\text{Total number of draws}} = \frac{2}{25} \]
Next, we calculate the experimental probability of drawing a number 3 counter given that a number 9 has already been drawn and replaced. The probability of drawing a number 3 counter is:
\[ P(3) = \frac{\text{Number of times 3 was drawn}}{\text{Total number of draws}} = \frac{3}{25} \]
Since the draws are independent (because the counter is replaced each time), we can find the combined probability of both events happening in sequence by multiplying the probabilities:
\[ P(9 \text{ followed by } 3) = P(9) \times P(3) = \frac{2}{25} \times \frac{3}{25} = \frac{6}{625} \]
Thus, the experimental probability of drawing a number 9 counter followed by a number 3 counter is:
\[ \frac{6}{625} \]
This result corresponds to none of the provided options (A, B, C, D) as they are not specified with values in your question. However, the finalized answer is \(\frac{6}{625}\).
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