Question
A 10-volt power supply is placed in series with two 5-ohm resistors. What is the current in the circuit after it passes through each of the two resistors?(1 point)
Responses
The current will stay the same at 1 amp after passing through both resistors.
The current will stay the same at 1 amp after passing through both resistors.
The current will stay the same at 2 amps after passing through both resistors.
The current will stay the same at 2 amps after passing through both resistors.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will drop to 1 amp after the first resistor and then to 0 amps after the second resistor.
Responses
The current will stay the same at 1 amp after passing through both resistors.
The current will stay the same at 1 amp after passing through both resistors.
The current will stay the same at 2 amps after passing through both resistors.
The current will stay the same at 2 amps after passing through both resistors.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will drop to 1 amp after the first resistor and then to 0 amps after the second resistor.
Answers
GPT-4o mini
To solve the problem, we first need to determine the total resistance in the circuit and then use Ohm's Law (V = I * R) to find the current.
1. **Calculate total resistance:**
Since the two 5-ohm resistors are in series, we add their resistances:
\[
R_{\text{total}} = R_1 + R_2 = 5 \, \Omega + 5 \, \Omega = 10 \, \Omega
\]
2. **Calculate current using Ohm's Law:**
The voltage of the power supply is 10 volts. We use Ohm's Law to find the current (I):
\[
I = \frac{V}{R_{\text{total}}} = \frac{10 \, \text{V}}{10 \, \Omega} = 1 \, \text{A}
\]
In a series circuit, the current remains the same throughout the circuit. Therefore, the current after passing through each of the two resistors will still be 1 amp.
**Correct response:**
The current will stay the same at 1 amp after passing through both resistors.
1. **Calculate total resistance:**
Since the two 5-ohm resistors are in series, we add their resistances:
\[
R_{\text{total}} = R_1 + R_2 = 5 \, \Omega + 5 \, \Omega = 10 \, \Omega
\]
2. **Calculate current using Ohm's Law:**
The voltage of the power supply is 10 volts. We use Ohm's Law to find the current (I):
\[
I = \frac{V}{R_{\text{total}}} = \frac{10 \, \text{V}}{10 \, \Omega} = 1 \, \text{A}
\]
In a series circuit, the current remains the same throughout the circuit. Therefore, the current after passing through each of the two resistors will still be 1 amp.
**Correct response:**
The current will stay the same at 1 amp after passing through both resistors.