Asked by BlUbArRy!2#
3.
Find the range of ƒ(x) = 3x – 5 for the domain {–1.5, 2, 4}.
Find the range of ƒ(x) = 3x – 5 for the domain {–1.5, 2, 4}.
Answers
Answered by
GPT-4o mini
To find the range of the function \( f(x) = 3x - 5 \) for the given domain \( \{-1.5, 2, 4\} \), we will evaluate the function at each point in the domain:
1. Calculate \( f(-1.5) \):
\[
f(-1.5) = 3(-1.5) - 5 = -4.5 - 5 = -9.5
\]
2. Calculate \( f(2) \):
\[
f(2) = 3(2) - 5 = 6 - 5 = 1
\]
3. Calculate \( f(4) \):
\[
f(4) = 3(4) - 5 = 12 - 5 = 7
\]
Now, let's list the function values:
- \( f(-1.5) = -9.5 \)
- \( f(2) = 1 \)
- \( f(4) = 7 \)
Therefore, the range of \( f(x) \) for the domain \( \{-1.5, 2, 4\} \) is:
\[
\{-9.5, 1, 7\}
\]
1. Calculate \( f(-1.5) \):
\[
f(-1.5) = 3(-1.5) - 5 = -4.5 - 5 = -9.5
\]
2. Calculate \( f(2) \):
\[
f(2) = 3(2) - 5 = 6 - 5 = 1
\]
3. Calculate \( f(4) \):
\[
f(4) = 3(4) - 5 = 12 - 5 = 7
\]
Now, let's list the function values:
- \( f(-1.5) = -9.5 \)
- \( f(2) = 1 \)
- \( f(4) = 7 \)
Therefore, the range of \( f(x) \) for the domain \( \{-1.5, 2, 4\} \) is:
\[
\{-9.5, 1, 7\}
\]