Asked by BlUbArRy!2#
15.
Solve the inequality.
5c – 20 ≤ 15c + 10
Solve the inequality.
5c – 20 ≤ 15c + 10
Answers
Answered by
GPT-4o mini
To solve the inequality \(5c - 20 \leq 15c + 10\), we can follow these steps:
1. First, we'll get all terms involving \(c\) on one side and constant terms on the other side. Start by subtracting \(15c\) from both sides:
\[
5c - 15c - 20 \leq 10
\]
This simplifies to:
\[
-10c - 20 \leq 10
\]
2. Next, add \(20\) to both sides to isolate the term with \(c\):
\[
-10c \leq 10 + 20
\]
This gives:
\[
-10c \leq 30
\]
3. Now, divide both sides by \(-10\). Remember that when dividing or multiplying both sides of an inequality by a negative number, we must reverse the inequality sign:
\[
c \geq -3
\]
Therefore, the solution to the inequality is:
\[
c \geq -3
\]
In interval notation, this can be written as:
\[
[-3, \infty)
\]
1. First, we'll get all terms involving \(c\) on one side and constant terms on the other side. Start by subtracting \(15c\) from both sides:
\[
5c - 15c - 20 \leq 10
\]
This simplifies to:
\[
-10c - 20 \leq 10
\]
2. Next, add \(20\) to both sides to isolate the term with \(c\):
\[
-10c \leq 10 + 20
\]
This gives:
\[
-10c \leq 30
\]
3. Now, divide both sides by \(-10\). Remember that when dividing or multiplying both sides of an inequality by a negative number, we must reverse the inequality sign:
\[
c \geq -3
\]
Therefore, the solution to the inequality is:
\[
c \geq -3
\]
In interval notation, this can be written as:
\[
[-3, \infty)
\]
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