Question

According to the data table, how much force is acting on the cart when the students measure an acceleration of 2.6 m/s^2? (Hint: the cart is he same cart for each trial)

Force acting on cart. Cart acceleration
(N) (m/s^2)
1. 0.2
2. 0.4
5. 1.0
6. 1.2
? 2.6

Enter a whole number only. No decimals , space , or symbol/letters

Answer 1

That is not the right answer

Answer 2

To find the force acting on the cart when the acceleration is 2.6 m/s², we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

where:
- \( F \) is the force,
- \( m \) is the mass of the cart,
- \( a \) is the acceleration.

From the provided data table, we can first find the mass of the cart by using one of the known force and acceleration pairs. For the first data row:

1. When force is 0.2 N, the acceleration is 0.2 m/s².
\[ F = m \cdot a \]
\[ 0.2 = m \cdot 0.2 \]
\[ m = \frac{0.2}{0.2} = 1 \text{ kg} \]

Now that we have the mass of the cart (1 kg), we can use it to find the force when the acceleration is 2.6 m/s²:

\[ F = m \cdot a \]
\[ F = 1 \cdot 2.6 \]
\[ F = 2.6 \text{ N} \]

Since we need to enter a whole number as the final answer:

**2**