To determine which table represents the function \( y = kf(x) \) where \( f(x) = |x + 4| \) vertically stretched by a factor of \( k = 3 \), we first need to understand how vertical stretching works.
The parent function \( f(x) = |x + 4| \) has specific output values for certain inputs:
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For \( x = 0 \): \[ f(0) = |0 + 4| = 4 \]
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For \( x = 1 \): \[ f(1) = |1 + 4| = 5 \]
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For \( x = 2 \): \[ f(2) = |2 + 4| = 6 \]
When we stretch the parent function by a factor of 3, we multiply the outputs by 3:
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For \( x = 0 \): \[ kf(0) = 3 \cdot 4 = 12 \]
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For \( x = 1 \): \[ kf(1) = 3 \cdot 5 = 15 \]
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For \( x = 2 \): \[ kf(2) = 3 \cdot 6 = 18 \]
Now, we look for a table that corresponds with the calculated values for \( kf(x) \):
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First Response:
- \( (0, -12) \)
- \( (1, -15) \)
- \( (2, -18) \)
- Does not match.
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Second Response:
- \( (0, 4) \)
- \( (1, 5) \)
- \( (2, 6) \)
- This is just the parent function, does not match.
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Third Response:
- \( (0, 1.3) \)
- \( (1, 1.7) \)
- \( (2, 2) \)
- Does not match.
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Fourth Response:
- \( (0, 12) \)
- \( (1, 15) \)
- \( (2, 18) \)
- This matches with our calculations.
Thus, the correct table showing \( y = kf(x) \) resulting in the parent function being vertically stretched by a factor of \( k = 3 \) is:
x y = kf(x)
- 0 12
- 1 15
- 2 18