Question
How much 0.150 M sodium hydroxide would be required to just neutralize 15 mL of 0.175M hydrochloric acid?
15mL x 0.150M/0.175M=12mL
correct!
15mL x 0.150M/0.175M=12mL
correct!
Answers
DrBob222
No.
mL NaOH x M NaOH = mL HCl x M HCl
I think you have some numbers reversed.
mL NaOH x M NaOH = mL HCl x M HCl
I think you have some numbers reversed.