What is the equivalent pair to (x^2) × (x^-2)

Question

1
x^10
(x^2) / (x^8)
1/x^6
(x^2) × (x^8)

Answer 1

To simplify the expression \((x^2) \times (x^{-2})\), we can use the law of exponents which states that when multiplying two expressions with the same base, we add the exponents.

\[ (x^2) \times (x^{-2}) = x^{2 + (-2)} = x^0 \]

Since any non-zero number raised to the power of 0 is 1, we have:

\[ x^0 = 1 \]

So, the equivalent of \((x^2) \times (x^{-2})\) is 1.

The correct answer from the options given is:

1