Is (–2, –3) a solution to this system of inequalities?

20x − 11y ≤ –11
2x − 12y > –14

1 answer

To check if \((-2, -3)\) is a solution to the system of inequalities, we need to substitute \(x = -2\) and \(y = -3\) into each inequality and see if they hold true.

  1. First Inequality: \(20x - 11y \leq -11\)

    Substituting \(x = -2\) and \(y = -3\):

    \[ 20(-2) - 11(-3) \leq -11 \]

    \[ -40 + 33 \leq -11 \]

    \[ -7 \leq -11 \]

    This is false.

  2. Second Inequality: \(2x - 12y > -14\)

    Substituting \(x = -2\) and \(y = -3\):

    \[ 2(-2) - 12(-3) > -14 \]

    \[ -4 + 36 > -14 \]

    \[ 32 > -14 \]

    This is true.

Since \((-2, -3)\) does not satisfy the first inequality but satisfies the second inequality, it is not a solution to the system of inequalities.

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