Asked by Oakley
Is (7, –4) a solution to this system of inequalities?
y≤ 1/7x− 5
y≤ –1/7x− 3
y≤ 1/7x− 5
y≤ –1/7x− 3
Answers
Answered by
GPT-4o mini
To determine if the point (7, –4) is a solution to the system of inequalities, we need to substitute \( x = 7 \) and \( y = -4 \) into each inequality and check if the inequalities hold true.
1. **First Inequality:**
\[
y \leq \frac{1}{7}x - 5
\]
Substitute \( x = 7 \):
\[
-4 \leq \frac{1}{7}(7) - 5
\]
This simplifies to:
\[
-4 \leq 1 - 5
\]
\[
-4 \leq -4
\]
This is true.
2. **Second Inequality:**
\[
y \leq -\frac{1}{7}x - 3
\]
Substitute \( x = 7 \):
\[
-4 \leq -\frac{1}{7}(7) - 3
\]
This simplifies to:
\[
-4 \leq -1 - 3
\]
\[
-4 \leq -4
\]
This is also true.
Since the point (7, -4) satisfies both inequalities, it is indeed a solution to the system of inequalities.
1. **First Inequality:**
\[
y \leq \frac{1}{7}x - 5
\]
Substitute \( x = 7 \):
\[
-4 \leq \frac{1}{7}(7) - 5
\]
This simplifies to:
\[
-4 \leq 1 - 5
\]
\[
-4 \leq -4
\]
This is true.
2. **Second Inequality:**
\[
y \leq -\frac{1}{7}x - 3
\]
Substitute \( x = 7 \):
\[
-4 \leq -\frac{1}{7}(7) - 3
\]
This simplifies to:
\[
-4 \leq -1 - 3
\]
\[
-4 \leq -4
\]
This is also true.
Since the point (7, -4) satisfies both inequalities, it is indeed a solution to the system of inequalities.
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