Asked by Oakley
or
Is (2, 10) a solution to this system of inequalities?
y ≥ x + 9
y > 3x + 3
Answers
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Answered by
GPT-4o mini
To determine if the point (2, 10) is a solution to the given system of inequalities, we'll substitute \( x = 2 \) and \( y = 10 \) into each inequality.
1. For the first inequality \( y \geq x + 9 \):
Substitute \( x = 2 \) into the inequality:
\[
y \geq 2 + 9 \implies y \geq 11
\]
Now, substituting \( y = 10 \):
\[
10 \geq 11 \quad \text{(False)}
\]
2. For the second inequality \( y > 3x + 3 \):
Substitute \( x = 2 \) into the inequality:
\[
y > 3(2) + 3 \implies y > 6 + 3 \implies y > 9
\]
Now, substituting \( y = 10 \):
\[
10 > 9 \quad \text{(True)}
\]
Since (2, 10) does not satisfy the first inequality but does satisfy the second, it is **not** a solution to the system of inequalities.
1. For the first inequality \( y \geq x + 9 \):
Substitute \( x = 2 \) into the inequality:
\[
y \geq 2 + 9 \implies y \geq 11
\]
Now, substituting \( y = 10 \):
\[
10 \geq 11 \quad \text{(False)}
\]
2. For the second inequality \( y > 3x + 3 \):
Substitute \( x = 2 \) into the inequality:
\[
y > 3(2) + 3 \implies y > 6 + 3 \implies y > 9
\]
Now, substituting \( y = 10 \):
\[
10 > 9 \quad \text{(True)}
\]
Since (2, 10) does not satisfy the first inequality but does satisfy the second, it is **not** a solution to the system of inequalities.
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