Asked by Anonymous
                what is the dimension of a rectangle whose perimeter is 228 and the length isf 42 feet longer that it is wide?
            
            
        Answers
                    Answered by
            Reiny
            
    width ---- x
length --- x+42
solve
2x + 2(x+42) = 228
    
length --- x+42
solve
2x + 2(x+42) = 228
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