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Asked by Anonymous

what is the dimension of a rectangle whose perimeter is 228 and the length isf 42 feet longer that it is wide?
15 years ago

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Answered by Reiny
width ---- x
length --- x+42

solve
2x + 2(x+42) = 228
15 years ago
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what is the dimension of a rectangle whose perimeter is 228 and the length isf 42 feet longer that it is wide?

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