Given that \( m∠8 = 45° \), we can use the properties of angles in a triangle. Since \( m∠8 \) is the angle formed by the slanting line on the left triangle and the horizontal base, the two triangles formed on the left and right sides of the trapezoid are right triangles.
In a right triangle, the sum of the angles is always \( 180° \). Therefore, the angles in each right triangle consist of the right angle, the angle at the base (which is \( m∠7 \) in your description), and the angle on the hypotenuse (which is \( m∠8 \)).
For the left triangle: \[ m∠7 + m∠8 + 90° = 180° \]
Substituting \( m∠8 \) with \( 45° \): \[ m∠7 + 45° + 90° = 180° \]
This simplifies to: \[ m∠7 + 135° = 180° \]
Now, subtract \( 135° \) from both sides: \[ m∠7 = 180° - 135° \] \[ m∠7 = 45° \]
Thus, you can write the equation to find \( m∠7 \) as: \[ m∠7 + 45° + 90° = 180° \]