To determine the value of \( x \) such that \( (x, 12, 2x + 3) \) forms a Pythagorean triple, we apply the Pythagorean theorem:
\[ a^2 + b^2 = c^2 \]
Here, we can identify:
- \( a = x \)
- \( b = 12 \)
- \( c = 2x + 3 \)
According to the Pythagorean theorem, we have:
\[ x^2 + 12^2 = (2x + 3)^2 \]
Now we can break down the equation step by step.
- Calculate \( 12^2 \):
\[ 12^2 = 144 \]
- Expand \( (2x + 3)^2 \):
\[ (2x + 3)^2 = 4x^2 + 12x + 9 \]
- Now substitute back into the equation:
\[ x^2 + 144 = 4x^2 + 12x + 9 \]
- Rearranging the equation gives:
\[ x^2 - 4x^2 - 12x + 144 - 9 = 0 \]
This simplifies to:
\[ -3x^2 - 12x + 135 = 0 \]
- Rearranging gives:
\[ 3x^2 + 12x - 135 = 0 \]
- Dividing the entire equation by 3 simplifies it to:
\[ x^2 + 4x - 45 = 0 \]
- Now we solve this quadratic equation using the factorization method. We need two numbers that multiply to -45 and add to 4.
These numbers are 9 and -5.
Thus, we can factor the quadratic as:
\[ (x + 9)(x - 5) = 0 \]
Setting each factor equal to zero gives:
\[ x + 9 = 0 \quad \text{or} \quad x - 5 = 0 \]
So, \( x = -9 \) or \( x = 5 \). Since x must be a positive value in a Pythagorean triple, we choose:
\[ x = 5 \]
Therefore, the value of \( x \) is \( 5 \). The answer is:
x = 5.