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Given that (x, 12, 2x+3) is a Pythagorean triple, what is the value of x ?

(1 point)
Responses

x=25x is equal to 25

x=9x is equal to 9

x=13x is equal to 13

x=5

1 answer

To determine the value of \( x \) such that \( (x, 12, 2x + 3) \) forms a Pythagorean triple, we apply the Pythagorean theorem:

\[ a^2 + b^2 = c^2 \]

Here, we can identify:

  • \( a = x \)
  • \( b = 12 \)
  • \( c = 2x + 3 \)

According to the Pythagorean theorem, we have:

\[ x^2 + 12^2 = (2x + 3)^2 \]

Now we can break down the equation step by step.

  1. Calculate \( 12^2 \):

\[ 12^2 = 144 \]

  1. Expand \( (2x + 3)^2 \):

\[ (2x + 3)^2 = 4x^2 + 12x + 9 \]

  1. Now substitute back into the equation:

\[ x^2 + 144 = 4x^2 + 12x + 9 \]

  1. Rearranging the equation gives:

\[ x^2 - 4x^2 - 12x + 144 - 9 = 0 \]

This simplifies to:

\[ -3x^2 - 12x + 135 = 0 \]

  1. Rearranging gives:

\[ 3x^2 + 12x - 135 = 0 \]

  1. Dividing the entire equation by 3 simplifies it to:

\[ x^2 + 4x - 45 = 0 \]

  1. Now we solve this quadratic equation using the factorization method. We need two numbers that multiply to -45 and add to 4.

These numbers are 9 and -5.

Thus, we can factor the quadratic as:

\[ (x + 9)(x - 5) = 0 \]

Setting each factor equal to zero gives:

\[ x + 9 = 0 \quad \text{or} \quad x - 5 = 0 \]

So, \( x = -9 \) or \( x = 5 \). Since x must be a positive value in a Pythagorean triple, we choose:

\[ x = 5 \]

Therefore, the value of \( x \) is \( 5 \). The answer is:

x = 5.