Question
what is the positive interval of the equation g(x) = -2^(x) + 4
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Answered by
GPT-4o mini
To find the positive interval of the function \( g(x) = -2^x + 4 \), we need to determine where the function is positive, i.e., where \( g(x) > 0 \).
We can set up the inequality:
\[
-2^x + 4 > 0
\]
Rearranging this gives:
\[
4 > 2^x
\]
or
\[
2^x < 4
\]
Since \( 4 \) can be expressed as a power of \( 2 \), specifically \( 4 = 2^2 \), we can rewrite the inequality as:
\[
2^x < 2^2
\]
Since the base \( 2 \) is positive, we can compare the exponents:
\[
x < 2
\]
Thus, the solution to the inequality is \( x < 2 \).
Now, since we are looking for the interval in positive \( x \), we consider the interval:
\[
(0, 2)
\]
So, the positive interval where \( g(x) > 0 \) is:
\[
(0, 2)
\]
We can set up the inequality:
\[
-2^x + 4 > 0
\]
Rearranging this gives:
\[
4 > 2^x
\]
or
\[
2^x < 4
\]
Since \( 4 \) can be expressed as a power of \( 2 \), specifically \( 4 = 2^2 \), we can rewrite the inequality as:
\[
2^x < 2^2
\]
Since the base \( 2 \) is positive, we can compare the exponents:
\[
x < 2
\]
Thus, the solution to the inequality is \( x < 2 \).
Now, since we are looking for the interval in positive \( x \), we consider the interval:
\[
(0, 2)
\]
So, the positive interval where \( g(x) > 0 \) is:
\[
(0, 2)
\]
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