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Apply the Triangle Inequality Theorem and determine which option could be the third side of a triangle if the first two sides m...
Apply the Triangle Inequality Theorem and determine which option could be the third side of a triangle if the first two sides measure 4 and 6.(1 point)
Responses
9
9
2
2
1
1
11
11
Responses
9
9
2
2
1
1
11
11
Answers
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Answered by
GPT-4o mini
The Triangle Inequality Theorem states that for any triangle with sides of lengths \( a \), \( b \), and \( c \), the following inequalities must hold:
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
Given sides of lengths 4 and 6, let's denote the unknown third side as \( x \). We need to apply the inequalities:
1. \( 4 + 6 > x \) → \( 10 > x \) → \( x < 10 \)
2. \( 4 + x > 6 \) → \( x > 2 \)
3. \( 6 + x > 4 \) → \( x > -2 \) (This is always true if \( x > 2 \))
From these inequalities, we have:
- \( x < 10 \)
- \( x > 2 \)
Therefore, the value of \( x \) must be in the range \( 2 < x < 10 \).
Now, let's examine the options:
- **9**: This is within the range \( 2 < x < 10 \). (Valid)
- **2**: This is not greater than 2. (Not valid)
- **1**: This is not within the range. (Not valid)
- **11**: This is greater than 10. (Not valid)
The only option that could be the third side of the triangle is **9**.
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
Given sides of lengths 4 and 6, let's denote the unknown third side as \( x \). We need to apply the inequalities:
1. \( 4 + 6 > x \) → \( 10 > x \) → \( x < 10 \)
2. \( 4 + x > 6 \) → \( x > 2 \)
3. \( 6 + x > 4 \) → \( x > -2 \) (This is always true if \( x > 2 \))
From these inequalities, we have:
- \( x < 10 \)
- \( x > 2 \)
Therefore, the value of \( x \) must be in the range \( 2 < x < 10 \).
Now, let's examine the options:
- **9**: This is within the range \( 2 < x < 10 \). (Valid)
- **2**: This is not greater than 2. (Not valid)
- **1**: This is not within the range. (Not valid)
- **11**: This is greater than 10. (Not valid)
The only option that could be the third side of the triangle is **9**.
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