Apply the Triangle Inequality Theorem and determine which option could be the third side of a triangle if the first two sides measure 4 and 6.(1 point)

Responses

9
9

2
2

1
1

11
11

1 answer

The Triangle Inequality Theorem states that for any triangle with sides of lengths \( a \), \( b \), and \( c \), the following inequalities must hold:

  1. \( a + b > c \)
  2. \( a + c > b \)
  3. \( b + c > a \)

Given sides of lengths 4 and 6, let's denote the unknown third side as \( x \). We need to apply the inequalities:

  1. \( 4 + 6 > x \) → \( 10 > x \) → \( x < 10 \)
  2. \( 4 + x > 6 \) → \( x > 2 \)
  3. \( 6 + x > 4 \) → \( x > -2 \) (This is always true if \( x > 2 \))

From these inequalities, we have:

  • \( x < 10 \)
  • \( x > 2 \)

Therefore, the value of \( x \) must be in the range \( 2 < x < 10 \).

Now, let's examine the options:

  • 9: This is within the range \( 2 < x < 10 \). (Valid)
  • 2: This is not greater than 2. (Not valid)
  • 1: This is not within the range. (Not valid)
  • 11: This is greater than 10. (Not valid)

The only option that could be the third side of the triangle is 9.