To determine the number of solutions for the quadratic equation \( y = 3x^2 + 2x + 1 \), we can use the discriminant from the quadratic formula, which is given by:
\[ D = b^2 - 4ac \]
In the equation \( ax^2 + bx + c = 0 \), we identify:
- \( a = 3 \)
- \( b = 2 \)
- \( c = 1 \)
Now we can calculate the discriminant:
\[ D = (2)^2 - 4(3)(1) = 4 - 12 = -8 \]
Since the discriminant \( D \) is negative (\( D < 0 \)), this means that the quadratic equation has:
- No real number solutions.
Therefore, the correct response is No real number solutions.