Question

Lateral surface of a cylinder with height of 11 and diameter of 14, use 3.14 for pi

Answer 1

To find the lateral surface area of a cylinder, you can use the formula:

\[
\text{Lateral Surface Area} = 2 \pi r h
\]

where \( r \) is the radius and \( h \) is the height of the cylinder.

Given:
- The height \( h = 11 \)
- The diameter \( d = 14 \)

First, we need to find the radius \( r \). The radius is half of the diameter:

\[
r = \frac{d}{2} = \frac{14}{2} = 7
\]

Now we can substitute the values into the formula:

\[
\text{Lateral Surface Area} = 2 \times 3.14 \times 7 \times 11
\]

Calculating step by step:

1. Multiply \( 2 \) and \( 3.14 \):
\[
2 \times 3.14 = 6.28
\]

2. Multiply \( 6.28 \) by \( 7 \):
\[
6.28 \times 7 = 43.96
\]

3. Multiply \( 43.96 \) by \( 11 \):
\[
43.96 \times 11 = 483.56
\]

Thus, the lateral surface area of the cylinder is:

\[
\text{Lateral Surface Area} \approx 483.56
\]

So, the lateral surface area of the cylinder is approximately **483.56 square units**.