To show that triangle \( ABC \) is congruent to triangle \( GHE \), we can describe a sequence of transformations that map triangle \( ABC \) onto triangle \( GHE \).
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Reflection: First, reflect triangle \( ABC \) across the y-axis. This transformation changes the x-coordinates of the vertices, resulting in the following vertices for triangle \( A'B'C' \):
- \( A'(−1, -3) \)
- \( B'(−1, -1) \)
- \( C'(−4, -3) \)
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Translation: Next, we will translate triangle \( A'B'C' \) downwards 7 units. This changes the y-coordinates of the vertices:
- \( A''(-1, -10) \)
- \( B''(-1, -8) \)
- \( C''(-4, -10) \)
However, we will need the final coordinates of \( GHE \) to match up directly, which means we might need to reconsider, as translation needs to align the points directly.
- Rotation: Instead, consider a rotation instead of direct downward translation. A \( 90^{\circ} \) rotation around the point that makes them coincide would help align them properly.
Ultimately, ensuring they share the same positioning and orientation would affirm their congruence.
Conclusion
To summarize, the transformations would be a reflection across the y-axis followed potentially by a rotation then possibly a slight translation if needed to overlap the triangles perfectly, demonstrating congruence through the defined transformations.