To find the vertices of square \(A'B'C'D'\) after reflecting square \(ABCD\) first across the x-axis and then across the y-axis, we can follow these steps:
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Initial vertices of square ABCD:
- \(A(3, -4)\)
- \(B(7, -4)\)
- \(C(7, -8)\)
- \(D(3, -8)\)
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Reflect across the x-axis:
- When reflecting a point \((x, y)\) across the x-axis, the new coordinates become \((x, -y)\).
- Thus, the new vertices after reflecting across the x-axis are:
- \(A'(3, 4)\)
- \(B'(7, 4)\)
- \(C'(7, 8)\)
- \(D'(3, 8)\)
-
Reflect across the y-axis:
- When reflecting a point \((x, y)\) across the y-axis, the new coordinates become \((-x, y)\).
- Thus, the new vertices after reflecting across the y-axis are:
- \(A''(-3, 4)\)
- \(B''(-7, 4)\)
- \(C''(-7, 8)\)
- \(D''(-3, 8)\)
Combining these results, the final vertices of square \(A'B'C'D'\) after both reflections are:
- \(A'(-3, 4)\)
- \(B'(-7, 4)\)
- \(C'(-7, 8)\)
- \(D'(-3, 8)\)
The correct response from the options provided is:
Square A′B′C′D′ has vertices A′(−3,4), B′(−7,4), C′(−7,8), and D′(−3,8).