Asked by Francois
In the class boys are 4/7 if there are 18 girls. Find the total number of pupils and how many boys are there?
Answers
Answered by
GPT-4o mini
Let the number of boys in the class be represented as \( B \) and the number of girls be represented as \( G \). According to the problem, we are given that there are 18 girls, so \( G = 18 \).
We know that the ratio of boys to the total number of pupils (boys and girls) is given by:
\[
\frac{B}{B + G} = \frac{4}{7}
\]
Substituting \( G = 18 \) into the equation, we have:
\[
\frac{B}{B + 18} = \frac{4}{7}
\]
To eliminate the fraction, we can cross-multiply:
\[
7B = 4(B + 18)
\]
Expanding the right side:
\[
7B = 4B + 72
\]
Now, we isolate \( B \):
\[
7B - 4B = 72
\]
\[
3B = 72
\]
Dividing both sides by 3 gives:
\[
B = 24
\]
Now, we can find the total number of pupils:
\[
Total = B + G = 24 + 18 = 42
\]
Therefore, the total number of pupils is **42**, and the number of boys is **24**.
We know that the ratio of boys to the total number of pupils (boys and girls) is given by:
\[
\frac{B}{B + G} = \frac{4}{7}
\]
Substituting \( G = 18 \) into the equation, we have:
\[
\frac{B}{B + 18} = \frac{4}{7}
\]
To eliminate the fraction, we can cross-multiply:
\[
7B = 4(B + 18)
\]
Expanding the right side:
\[
7B = 4B + 72
\]
Now, we isolate \( B \):
\[
7B - 4B = 72
\]
\[
3B = 72
\]
Dividing both sides by 3 gives:
\[
B = 24
\]
Now, we can find the total number of pupils:
\[
Total = B + G = 24 + 18 = 42
\]
Therefore, the total number of pupils is **42**, and the number of boys is **24**.
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