To determine which table shows the vertical stretch of the parent function \( y = |x + 4| \) by a factor of \( k = 3 \), we first need to find the points on the parent function and then apply the vertical stretch.
The parent function \( y = |x + 4| \) at various points:
- At \( x = 0 \): \( y = |0 + 4| = 4 \)
- At \( x = 1 \): \( y = |1 + 4| = 5 \)
- At \( x = 2 \): \( y = |2 + 4| = 6 \)
Now, applying the vertical stretch by a factor of \( k = 3 \):
- For \( x = 0 \): \( y = 3 \cdot 4 = 12 \)
- For \( x = 1 \): \( y = 3 \cdot 5 = 15 \)
- For \( x = 2 \): \( y = 3 \cdot 6 = 18 \)
Now let's look at the provided responses for \( y = kf(x) \):
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Table 1:
- \( (0, 4) \)
- \( (1, 5) \)
- \( (2, 6) \)
- Incorrect (these values are not the result of a vertical stretch)
-
Table 2:
- \( (0, -12) \)
- \( (1, -15) \)
- \( (2, -18) \)
- Incorrect (values are negative)
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Table 3:
- \( (0, 12) \)
- \( (1, 15) \)
- \( (2, 18) \)
- Correct (these values match the expected results of stretching by a factor of 3)
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Table 4:
- \( (0, 1.3) \)
- \( (1, 1.7) \)
- \( (2, 2) \)
- Incorrect (values are much lower than expected)
Thus, the correct table showing that \( y = kf(x) \) results in the parent function \( y = |x + 4| \) being vertically stretched by a factor of \( k = 3 \) is Table 3.