Question

put in decreasing freezing point 0.10m Na3PO4,0.35m NaCl,0.20 m MgCl2, 0.15 m C6H12O6,0.15 m CH3COOH
delta T = i*Kf*m
Since Kf is a constant you may ignore it and multiply i*m. The largest number will be the largest delta T.
Arrenge Na3PO4 m, 0.35 m NaCl,0.2m MgCl2m,0.15m C6H12O6 m, 0.15CH3COOH m in decreasing order of their expected freezing point

Related Questions

How many milliliters of 0.0850 M Na3PO4(aq) will react with 22.00 mL of 0.0800 M MgCl2(aq)? 3 MgC... How do you arrange these aqueous solutions in order of decreasing freezing point: 0.10 m Na3PO4, 0.3... what is the freezing point of 0.05 M glucose(C6H12O6), 0.05 M NaCl, and 0.05 M MgCl2? Arrange the following aqueous solutions in order of decreasing freezing points (lowest to highest te...