The decomposition of silver bromide (AgBr) can be represented by the following chemical equation:
\[ 2 , \text{AgBr} , \rightarrow , 2 , \text{Ag} , + , \text{Br}_2 \]
From the balanced equation, we can see that for every 2 moles of silver bromide that decompose, 2 moles of silver (Ag) and 1 mole of bromine (Br\(_2\)) are produced.
This means the ratio of silver to bromine is \(2:1\).
Thus, the correct answer is:
2:1