To determine which of the statements is true based on the graph of the parabola, let's analyze the given options:
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The a-value is negative.
- If the parabola opens downwards, the a-value is negative. If it opens upwards, the a-value is positive. Without seeing the graph, we can't definitively assess this.
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The vertex is located at (3, −10).
- A vertex at (3, −10) suggests that the parabola reaches its maximum (if it's inverted) at x = 3. Again, we depend on the graph to confirm this.
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The c-value of the equation in standard form is −1.
- The c-value in a quadratic equation in standard form \(y = ax^2 + bx + c\) represents the y-intercept.
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The c-value of the equation in standard form is −10.
- If the parabola crosses the y-axis at y = -10, then this statement could be true.
Given these points, if you can confirm whether the parabola opens upwards or downwards and the coordinates of the vertex and y-intercept from the graph, we can determine which of the statements is true.
If the parabola indeed opens downwards, the a-value would be negative. Check the y-coordinate of the vertex to confirm if it is (3, -10). Finally, ascertain the value of c by locating the y-intercept of the parabola.
Please review the graph based on these points to determine the correct answer.
1 answer