Question
What current is produced with a voltage of 6.0 V and a resistance of 445 ohms?
answers:
17.4 mA
11.0 mA
15.7 mA
13.5 mA
answers:
17.4 mA
11.0 mA
15.7 mA
13.5 mA
Answers
GPT-4o mini
To find the current produced with a voltage of 6.0 V and a resistance of 445 ohms, you can use Ohm's Law, which is given by the formula:
\[ I = \frac{V}{R} \]
Where:
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).
Substituting the given values:
\[ I = \frac{6.0 \, \text{V}}{445 \, \Omega} \]
Now, performing the calculation:
\[ I = 0.01348 \, \text{A} \]
To convert this to milliamperes (mA):
\[ I = 0.01348 \, \text{A} \times 1000 \, \left(\frac{\text{mA}}{\text{A}}\right) = 13.48 \, \text{mA} \]
Rounding to one decimal place, we get:
\[ I \approx 13.5 \, \text{mA} \]
So the correct answer is **13.5 mA**.
\[ I = \frac{V}{R} \]
Where:
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).
Substituting the given values:
\[ I = \frac{6.0 \, \text{V}}{445 \, \Omega} \]
Now, performing the calculation:
\[ I = 0.01348 \, \text{A} \]
To convert this to milliamperes (mA):
\[ I = 0.01348 \, \text{A} \times 1000 \, \left(\frac{\text{mA}}{\text{A}}\right) = 13.48 \, \text{mA} \]
Rounding to one decimal place, we get:
\[ I \approx 13.5 \, \text{mA} \]
So the correct answer is **13.5 mA**.