Question

Triangle MNO
is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)
left parenthesis negative 2 comma negative 1 right parenthesis

(−2,−11)

Answer 1

To find the new coordinates of point \( N \) after translating it, we need to apply the translation rules:

1. To translate a point up by a certain number of units, we add that number to the y-coordinate.
2. To translate a point left by a certain number of units, we subtract that number from the x-coordinate.

Given that point \( N \) is located at (0, -6) and we need to:

- Translate up 5 units: \( -6 + 5 = -1 \)
- Translate left 2 units: \( 0 - 2 = -2 \)

So, the new coordinates \( N' \) are \( (-2, -1) \).

Thus, the coordinates of \( N' \) are:

**(−2,−1)**.