During a lab experiment, the temperature of a liquid changes from 625°F to 1034°F.

What is the percent of increase in the temperature of the liquid?

Enter your answer in the box as a percent rounded to the nearest hundredth.

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1 answer

To find the percent increase in temperature, you can use the following formula:

\[ \text{Percent Increase} = \left( \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \right) \times 100 \]

In this case, the old value (initial temperature) is 625°F and the new value (final temperature) is 1034°F.

First, calculate the difference:

\[ \text{New Value} - \text{Old Value} = 1034°F - 625°F = 409°F \]

Now, plug the values into the formula:

\[ \text{Percent Increase} = \left( \frac{409°F}{625°F} \right) \times 100 \]

Calculate the fraction:

\[ \frac{409}{625} \approx 0.6544 \]

Now multiply by 100 to find the percent:

\[ 0.6544 \times 100 \approx 65.44 \]

Thus, the percent increase in the temperature of the liquid is:

\[ \boxed{65.44} \]