Asked by ami

If 0.0490g of AgIO3 DISOLVES per liter of solution, calculate the solubility product constant.
Answered by DrBob222
AgIO3 ==> Ag^+ + IO3^-

Ksp = (Ag^+)(IO3^-)

Solubility
AgIO3 = grams/molar mass.
Plug that in for Ag^+ and for IO3^- and calculate Ksp.
Answered by n
1.73*10^-4
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