Two tables were generated to compare the functions f(x) and g(x)=f(x)−1. Find the missing value in the table for the function g(x).(1 point)

Question

 

x f(x)
0 0
−1 1
2 4
x g(x)
0 −1
−1
2 3

Answer 1

To find the missing value in the table for the function \( g(x) = f(x) - 1 \), we first need to use the values given in the table for \( f(x) \).

Here are the steps:

1. When \( x = 0 \): \[ f(0) = 0 \] Therefore, \[ g(0) = f(0) - 1 = 0 - 1 = -1 \]

2. Next, for \( x = -1 \): \[ f(-1) = 1 \] Thus, \[ g(-1) = f(-1) - 1 = 1 - 1 = 0 \]

3. Finally, when \( x = 2 \): \[ f(2) = 4 \] Therefore, \[ g(2) = f(2) - 1 = 4 - 1 = 3 \]

Now, we can summarize the values for \( g(x) \):

• For \( x = 0 \): \( g(0) = -1 \)
• For \( x = -1 \): \( g(-1) = 0 \)
• For \( x = 2 \): \( g(2) = 3 \)

Thus, the missing value for \( g(-1) \) is 0.

So the completed table for \( g(x) \) is:

\[ \begin{align*} x & \quad g(x) \ 0 & \quad -1 \ -1 & \quad 0 \ 2 & \quad 3 \ \end{align*} \]

The missing value is 0.