You use scale factor of 3/4 to create a dilated circle with a radius of 9 inches. What si the radius of the original circle?

1 answer

To find the radius of the original circle before the dilation, you can use the scale factor of the dilation. The relationship between the original radius (let's denote it as \( r \)) and the dilated radius (which is given as 9 inches) can be expressed as:

\[ \text{dilated radius} = \text{original radius} \times \text{scale factor} \]

Substituting the values we have:

\[ 9 = r \times \frac{3}{4} \]

To isolate \( r \), you can rearrange the equation:

\[ r = 9 \div \frac{3}{4} \]

Dividing by a fraction is the same as multiplying by its reciprocal:

\[ r = 9 \times \frac{4}{3} \]

Now, calculate \( r \):

\[ r = \frac{9 \times 4}{3} = \frac{36}{3} = 12 \]

So, the radius of the original circle is \( \boxed{12} \) inches.