Triangle ABC has vertices point A (-2,-2), Point B( (-4,-3), And Point C (-2,-5). Find the coordinates of A' B' And C' after a dilation with a scale factor of 3 and a center point of dilation at the origin

1 answer

To find the coordinates of the points \( A' \), \( B' \), and \( C' \) after a dilation with a scale factor of 3 and the center of dilation at the origin, we can use the formula for dilation. The formula for the coordinates of a point \( (x, y) \) after a dilation from the origin by a scale factor \( k \) is:

\[ (x', y') = (kx, ky) \]

Given the vertices of triangle \( ABC \):

  • Point \( A(-2, -2) \)
  • Point \( B(-4, -3) \)
  • Point \( C(-2, -5) \)

Let's calculate the new coordinates.

  1. For point \( A(-2, -2) \): \[ A' = (3 \cdot -2, 3 \cdot -2) = (-6, -6) \]

  2. For point \( B(-4, -3) \): \[ B' = (3 \cdot -4, 3 \cdot -3) = (-12, -9) \]

  3. For point \( C(-2, -5) \): \[ C' = (3 \cdot -2, 3 \cdot -5) = (-6, -15) \]

Thus, the coordinates after dilation are:

  • \( A'(-6, -6) \)
  • \( B'(-12, -9) \)
  • \( C'(-6, -15) \)

So, the final answer is:

  • \( A' = (-6, -6) \)
  • \( B' = (-12, -9) \)
  • \( C' = (-6, -15) \)