To find out how much larger the diameter of the Sun is than the orbital distance of the Moon from Earth, we need to subtract the orbital distance of the Moon from the diameter of the Sun:
- Diameter of the Sun: \( 1.39 \times 10^9 \) meters
- Orbital distance of the Moon: \( 3.84 \times 10^8 \) meters
Now, perform the subtraction:
\[ 1.39 \times 10^9 - 3.84 \times 10^8 \]
To do this subtraction, we should express both numbers in a similar format:
Convert \( 1.39 \times 10^9 \) into the same exponent as \( 3.84 \times 10^8 \):
\[ 1.39 \times 10^9 = 13.9 \times 10^8 \]
Now we can perform the subtraction:
\[ 13.9 \times 10^8 - 3.84 \times 10^8 = (13.9 - 3.84) \times 10^8 = 10.06 \times 10^8 \]
Now, convert \( 10.06 \times 10^8 \) back to standard scientific notation:
\[ 10.06 \times 10^8 = 1.006 \times 10^9 \]
Thus, the diameter of the Sun is \( 1.006 \times 10^9 \) meters larger than the orbital distance of the Moon from Earth.
In standard notation, this is:
\[ 1,006,000,000 \text{ meters} \]
Therefore, the correct response is:
1,006,000,000 meters