Use the image to answer the question.

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.

Translate figure PQRS
6 units down and 2 units to the right. What are the coordinates of P′
?

(1 point)
Responses

(10, 4)
left parenthesis 10 comma 4 right parenthesis

(2, 0)
left parenthesis 2 comma 0 right parenthesis

(2, 12)
left parenthesis 2 comma 12 right parenthesis

(6, 0)

1 answer

To translate the point P(4, 6) 6 units down and 2 units to the right, we perform the following calculations:

  1. Move 2 units to the right:

    • x-coordinate: 4 + 2 = 6
  2. Move 6 units down:

    • y-coordinate: 6 - 6 = 0

So the new coordinates of P′ after the translation are (6, 0).

The correct answer is: (6, 0)

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