To find the equation of the linear function that models the relationship shown in the table, we can use the two points provided: (4, 38) and (6, 58).
First, we calculate the slope \( m \):
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
Next, we can use the point-slope form of the linear equation \( y - y_1 = m(x - x_1) \). We can use one of the points for this. Let's use the point (4, 38):
\[ y - 38 = 10(x - 4) \]
Expanding this:
\[ y - 38 = 10x - 40 \] \[ y = 10x - 40 + 38 \] \[ y = 10x - 2 \]
So the equation of the linear function that models the relationship shown in the table is:
\[ \boxed{y = 10x - 2} \]
Thus, the correct response is:
y = 10x - 2.