To find the remainder when \( f(x) = 5x^5 + 3x^3 + 2 \) is divided by \( x - 2 \), we will use the Remainder Theorem which states that the remainder of \( f(x) \) divided by \( x - c \) is \( f(c) \).
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We need to evaluate \( f(2) \): \[ f(2) = 5(2^5) + 3(2^3) + 2 \]
Now calculating each term: \[ 2^5 = 32 \quad \Rightarrow \quad 5(32) = 160 \] \[ 2^3 = 8 \quad \Rightarrow \quad 3(8) = 24 \] \[ \text{So, } f(2) = 160 + 24 + 2 = 186 \]
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Therefore, the remainder when \( f(x) \) is divided by \( x - 2 \) is \( 186 \).
Next, we are tasked with finding the remainder when \( f(x) \) is divided by \( x - 2 \) using the above steps.
- According to the remainder theorem, the remainder of \( f(x) \) divided by \( (x-2) \) is equal to: \[ f(2) = 186 \]
In summary, the remainder when \( f(x) = 5x^5 + 3x^3 + 2 \) is divided by \( x - 2 \) is \( \boxed{186} \).