6ln(x+8)+1/8lnx-ln(cosx)
3 answers
what about it ?
how do I rewrite it as a single logarithm
6ln(x+8)+1/8lnx-ln(cosx)
= ln[(x+8)^6] - ln(x^(1/8)) - ln(cosx)
= ln [(x+8)^6/(x^(1/8)cosx)
= ln[(x+8)^6] - ln(x^(1/8)) - ln(cosx)
= ln [(x+8)^6/(x^(1/8)cosx)