To solve the inequality \( x^2 - 8 < 1 \), we first rearrange it:
\[ x^2 - 8 < 1 \] \[ x^2 < 9 \]
Now, we take the square root of both sides, remembering that this will give us two inequalities:
\[ -\sqrt{9} < x < \sqrt{9} \] \[ -3 < x < 3 \]
Thus, the solution set is:
\[ (-3, 3) \]
Now, let's analyze the options you've provided:
- \( x > 18 \)
- \( x < 18 \)
- \( x < 11 \)
- \( x > 4.5 \)
None of these options reflect the correct solution to the inequality \( -3 < x < 3 \). However, if you're looking for the closest answer or if there's a misunderstanding, please let me know!