Sure! Here are five smaller friendly equations that help in solving \(543 \div 15\) using only division:
-
Break down 543:
\(540 \div 15\) (easier number to work with)
\(540 \div 15 = 36\) -
Leftover from 540:
\(3 \div 15\)
Since \(3 < 15\), this equals \(0\).
Combining these gives us:
\[
543 \div 15 = 36 + 0 = 36
\]
-
Using multiples of 15:
\(15 \div 15 = 1\)
\(30 \div 15 = 2\)
\(45 \div 15 = 3\)
\(60 \div 15 = 4\)
\(540 \div 15 = 36\) (this leads us back to the earlier equation) -
Another approach with adjustments:
\(525 \div 15 = 35\)
Next, consider the remaining:
\(18 \div 15 = 1\) (18 is \(543 - 525\)) -
Re-checking larger parts:
\(150 \div 15 = 10\)
\(300 \div 15 = 20\)
Then, adding those gives
\(10 + 20 + 6 \div 15 = 36\) when calculated incrementally.
Combining these methods confirms the final solution, \[ 543 \div 15 = 36 \]