Question
Elemental analysis is performed on an unknown organic substance which is found to contain 6 grams of hydrogen and 36 grams of carbon. What is the empirical formula for this unknown?
Group of answer choices
CH4
CH2
CH3
CH
Group of answer choices
CH4
CH2
CH3
CH
Answers
GPT-4o mini
To determine the empirical formula of the unknown organic substance, we first need to find the number of moles of carbon and hydrogen present in the sample.
1. **Calculate moles of carbon (C)**:
- Atomic mass of carbon = 12 g/mol
- Mass of carbon = 36 g
- Moles of carbon = mass / molar mass = 36 g / 12 g/mol = 3 moles
2. **Calculate moles of hydrogen (H)**:
- Atomic mass of hydrogen = 1 g/mol
- Mass of hydrogen = 6 g
- Moles of hydrogen = mass / molar mass = 6 g / 1 g/mol = 6 moles
3. **Find the simplest mole ratio**:
- The ratio of carbon to hydrogen is 3 moles C to 6 moles H.
- To simplify, divide both values by the smaller number of moles (which is 3):
- C: 3/3 = 1
- H: 6/3 = 2
4. **Write the empirical formula**:
- The empirical formula based on the simplest ratio is \( \text{CH}_2 \).
Thus, the empirical formula for this unknown substance is **CH2**.
1. **Calculate moles of carbon (C)**:
- Atomic mass of carbon = 12 g/mol
- Mass of carbon = 36 g
- Moles of carbon = mass / molar mass = 36 g / 12 g/mol = 3 moles
2. **Calculate moles of hydrogen (H)**:
- Atomic mass of hydrogen = 1 g/mol
- Mass of hydrogen = 6 g
- Moles of hydrogen = mass / molar mass = 6 g / 1 g/mol = 6 moles
3. **Find the simplest mole ratio**:
- The ratio of carbon to hydrogen is 3 moles C to 6 moles H.
- To simplify, divide both values by the smaller number of moles (which is 3):
- C: 3/3 = 1
- H: 6/3 = 2
4. **Write the empirical formula**:
- The empirical formula based on the simplest ratio is \( \text{CH}_2 \).
Thus, the empirical formula for this unknown substance is **CH2**.