To find the missing value that makes the point (3, __) on the equation \( y = 7x^2 + 3 \), substitute \( x = 3 \) into the equation.
\[ y = 7(3^2) + 3 \]
Calculating \( 3^2 \):
\[ 3^2 = 9 \]
Now substitute that value back into the equation:
\[ y = 7(9) + 3 \]
Calculating \( 7 \times 9 \):
\[ 7 \times 9 = 63 \]
Now, add 3:
\[ y = 63 + 3 = 66 \]
So the missing value is:
\[ \boxed{66} \]
Thus, the point is (3, 66).