Find the missing value to make the point (5, __) on the equation y=−5x2+11

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To find the missing value for the point \((5, __)\) on the equation \(y = -5x^2 + 11\), we need to substitute \(x = 5\) into the equation.

Let's do the calculation:

\[ y = -5(5)^2 + 11 \]

First, calculate \(5^2\):

\[ 5^2 = 25 \]

Now, substitute that back into the equation:

\[ y = -5(25) + 11 \]

Calculate \(-5(25)\):

\[ -5(25) = -125 \]

Now add 11:

\[ y = -125 + 11 = -114 \]

So, the missing value is:

\[ y = -114 \]

Thus, the point is \((5, -114)\).