Asked by sha
a store sells cashews for $5.00 per pound and peanuts for $1.50 per pound. the manager decides to mix 30 pounds of peanuts with some cashews and sell the mixture for $3.00 per pound. how many pounds of cashews should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts separately?
Answers
Answered by
MathMate
Equate total selling price of mixture to total selling price of components. Solve for weight of cashews.
Let
x=weight of cashews to be added
Total price of mixture
= 3(30+x)
Total price of components
= 30*1.5 + 5x
Equate and solve for x:
3(30+x) = 30*1.5 + 5x
Isolate x and solv
5x-3x = 3(30)-30(1.5)
2x = 45
x = 22.5 lbs
Let
x=weight of cashews to be added
Total price of mixture
= 3(30+x)
Total price of components
= 30*1.5 + 5x
Equate and solve for x:
3(30+x) = 30*1.5 + 5x
Isolate x and solv
5x-3x = 3(30)-30(1.5)
2x = 45
x = 22.5 lbs
Answered by
sha
thanks a million!
Answered by
Anonymous
The grocery store sells kumquats for $3.75 a pound and Asian pears for $2.25 a pound. Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $14.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.