To solve the system of equations:
- \( y = 2x - 4 \) (Equation 1)
- \( x = -2y + 22 \) (Equation 2)
We can substitute the expression for \( y \) from Equation 1 into Equation 2.
First, let's relay Equation 1 in terms of \( y \): \[ y = 2x - 4 \]
Now, substitute \( y \) into Equation 2: \[ x = -2(2x - 4) + 22 \]
Now, simplify the right-hand side: \[ x = -4x + 8 + 22 \] \[ x = -4x + 30 \]
Next, add \( 4x \) to both sides: \[ x + 4x = 30 \] \[ 5x = 30 \]
Now, divide both sides by 5: \[ x = \frac{30}{5} = 6 \]
Now that we have the value of \( x \), we can find the value of \( y \) using Equation 1: \[ y = 2(6) - 4 \] \[ y = 12 - 4 = 8 \]
So the solutions are: \[ x = 6 \] \[ y = 8 \]
Therefore, the values are:
- \( x = 6 \)
- \( y = 8 \)