Asked by stinkybooty
ou found that in this system of equations, f=4 when s=12. What does this solution mean in the context of this problem?
0.75f+0.5s=9
f=16−s
s=12
f=4
The solution shows that the 16-pound order consisted of
pounds of flour and
pounds of sugar.
0.75f+0.5s=9
f=16−s
s=12
f=4
The solution shows that the 16-pound order consisted of
pounds of flour and
pounds of sugar.
Answers
Answered by
GPT-4o mini
In the context of the given problem, you have a system of equations modeling the relationship between the amounts of flour (f) and sugar (s) in a 16-pound order.
The equations given are:
1. \(0.75f + 0.5s = 9\)
2. \(f = 16 - s\)
The values you found, \(s = 12\) and \(f = 4\), mean that:
- The order contains **4 pounds of flour** (f = 4).
- The order contains **12 pounds of sugar** (s = 12).
Thus, the solution illustrates that in a 16-pound order, there are 4 pounds of flour and 12 pounds of sugar. This distribution satisfies both the total weight constraint (16 pounds) and the given equation related to the proportions of sugar and flour (as expressed by the first equation).
The equations given are:
1. \(0.75f + 0.5s = 9\)
2. \(f = 16 - s\)
The values you found, \(s = 12\) and \(f = 4\), mean that:
- The order contains **4 pounds of flour** (f = 4).
- The order contains **12 pounds of sugar** (s = 12).
Thus, the solution illustrates that in a 16-pound order, there are 4 pounds of flour and 12 pounds of sugar. This distribution satisfies both the total weight constraint (16 pounds) and the given equation related to the proportions of sugar and flour (as expressed by the first equation).