A triangle has angle measures of 75°

, 41°
, and (3x+19)°
. Solve for x.(1 point)

1 answer

In a triangle, the sum of the angle measures is always 180 degrees. Given the angles \( 75^\circ \), \( 41^\circ \), and \( (3x + 19)^\circ \), we can set up the following equation:

\[ 75 + 41 + (3x + 19) = 180 \]

Now, let's simplify the left side of the equation:

\[ 75 + 41 = 116 \] \[ 116 + (3x + 19) = 180 \]

So we have:

\[ 116 + 3x + 19 = 180 \]

Now, combine the constants:

\[ 135 + 3x = 180 \]

Next, isolate \( 3x \) by subtracting 135 from both sides:

\[ 3x = 180 - 135 \] \[ 3x = 45 \]

Now, divide both sides by 3:

\[ x = \frac{45}{3} = 15 \]

So the solution for \( x \) is:

\[ \boxed{15} \]